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Next Topper Institute – All India      Guided by Rohann Sir
Next Topper Institute is a modern and result-oriented educational platform committed to providing quality competitive exam preparation across India, including Jind, Delhi, Patna, and other regions. Under the expert guidance of Rohann Sir, the institute focuses on transforming students into confident performers through concept clarity, smart strategies, and disciplined practice.
 
Vision & Mission
The mission of Next Topper Institute is to make high-level education accessible to every student, regardless of city or background. The institute believes that with the right mentorship and structured guidance, any student can become a topper.
Core values include:

Logical and analytical thinking
Exam-oriented preparation
Continuous evaluation and improvement
Student motivation and confidence building
Courses Offered
Next Topper Institute offers comprehensive coaching programs for:
JEE Main & Advanced
NEET (UG)
Board Exams (CBSE & State Boards)
Crash Courses & One-Day Revision Programs
Previous Year Question (PYQ) Based Practice
Special Chapter-Wise & Full Syllabus Coverage
Teaching Methodology
The teaching approach led by Rohann Sir is simple, systematic, and effective:
Concepts taught from basic to advanced level
Numerical problems solved step-by-step
Focus on understanding rather than rote learning
Smart techniques introduced only after concept mastery
Regular tests, assignments, and doubt-solving sessions
Online & Offline Learning Model                         

To support students from Jind, Delhi, Patna, and all over India, Next Topper Institute follows a hybrid education system:
Offline classroom programs (location-wise)
Online live interactive classes
Recorded video lectures for revision
Digital notes, PDFs, and practice sheets☝☝☝
Continuous student support through online platforms
Why Choose Next Topper Institute?
All-India level guidance by Rohann Sir
Student-friendly teaching style
Affordable and transparent fee structure
Concept-based + exam-focused learning
Personalized attention and mentorship
Proven improvement in student performance
Learning Environment
The institute promotes a positive, disciplined, and motivating learning environment where students are encouraged to ask questions, think critically, and develop exam confidence.

Next topper institute

class 10 ohm's law

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class 10 video  what ohm's law? Ohm’s Law states that the current flowing through a conductor is directly proportional to the potential difference applied across its ends, provided the temperature and other physical conditions remain unchanged. Mathematically it can be represented as, objective question based on electric current open this link for objective    https://nexttopperinstitute.blogspot.com/2020/07/class-10th-objective-questions-on.html   Class 10       HOW TO ORGANISM REPRODUCE Question. 1(i) What is fertilisation? Distinguish between external fertilisation and internal fertilisation. (ii) What is the site of fertilisation in human beings? Answer. (i) Fertilisation is defined as the fusion of a male gamete (sperm) with a female gamete (an ovum or egg) to form a zygote during sexual reproduction. (ii) The site of fertilisation in human beings is in the fallopian tube of female reproductive system. Question.2 Define th...
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error analysis objective questions dpp

NEXT TOPPER INSTITUTE  FOR YOU  1.     In an experiment the percentage of error occurred in the measurement of physical quantities A,B,C and D   are 1% ,2%, 3% and 4% respectively . then the maximum percentage of error in the measurement x where x =A 2 B 1/2 /c 1/3 D 3 will be                                             NEET 2019 a.      10%                b. 3/13%                c.   -10%                                d. 16% 2.   ...
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Kirchhoff law problem and equivalent resistance

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1. using Kirchhoff law find the current in following branch answer     AB:(5/8) A, CA: (5/2) A, DEB: (15/8) A AD: (15/8) A, CD: 0 A, BC: (5/2) A 2.  using Kirchhoff law find the current in following branch   Answer  current in branch AB= (4/17) A In branch BC = (6/17) A In branch CD = (4/17) A In branch AD= (6/17) A In branch BD = (-2/17) A Total Current =(4/17) +(6/17)+(-4/17)+(6/17)+(-2/17)=(10/17) A 4. find R Equivalent 
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class 12 chapter 3 current questions

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1.   Calculate i 1 , i 2 , i 3 2.   Calculate current in each branch  Using Kirchhoff’s rules                                           cbse 2017      3. calculate the current through the 40 Ω and 20 Ω resistors in the following circuit : Using Kirchhoff’s rules, cbse 2019  4.
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current chapter 3 class 12 objective dpp2

please comments your answer for matching    NEXT TOPPER INSTITUTE  हम आपके सपनो को साकार  करेंगे 1.     A wire of length 6 m and area of cross section 1 m m  2 carries a current of 2 A. if unit cubic meter of the material of a wire contains 10 29        free electrons ,find the average time taken by an electron to cross the length of wire . 16 hr            b. 13.33 hr           c. 14.44 hr                      d. 17 hr 2.     The number of density of electrons in coppers is 8.5 x 10  28  m -3 . What is the time taken by an electron to drift from one end of the wire 2.2 m long to its other end if area of cross section of the wire is 2.0 x 10 -6  m  2 and it is carryin...
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class 10 chapter 10 cbse previous year all question

1.     NEXT TOPPER INSTITUTE हम आपके सपनो को साकार करेंगे   An object 3.0 cm high is placed perpendicular to the principal axis of a concave lens of focal length 30 . the image is formed at a distance of 10.cm from the lens calculate   distance at which object is placed ,size and nature of image formed . 2.     A concave lens has focal length of 20 cm .at what distance from the lens ,a 5  cm tall object be placed so that it formed an image at 15 cm from the lens . also calculate the size of the image formed ? 3.     Find the power of a concave lens of focal length 2 m. 4.     An object of height 5  cm is placed perpendicular to the principal axis of a concave lens of focal length 10 cm. if the distance of the object from the optical center  of the lens is 20 cm determine the position ,nature and size of the image formed using the lens formula . 5.     The image of an object formed by a...
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current objective question for cbse, jee , neet class12 chapter 3

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NEXT TOP PER INSTITUTE Dpp current questions 1.      1.  How many electrons per second flow through the cross sectional of a conductor so that the conductor carries a current of 1 ampere? a.      6.00 x 10 16 /sec       b.       6.00 x 10 17 /sec          c.        6.00 x 10 19 /sec     d.  6.25 x 10 18 /sec .       2.     2.   In a discharge tube the number of hydrogen ions drifting across a cross section per second is 1.0 X 10 18 , while the number of electrons drifting in opposite direction across that of cross section is 2.7 x 10 18  per second . calculate the total current crossing the given cross section . a.        0.6 A                        ...
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Motilal nehru public school jind class 9th dpp 1 Newton's law of motion all level question

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please download in pdf  click here  👇👇👇👇👇👇👇👇 https://knowingonline.in/2020/07/27/class-ix-newtons-law-of-motion/ Question 1. Deduce Newton’s first law from the second law. Question 2. When small boy is trying to push a heavy stone, mention various forces acting on the stone. Question 3. Describe in brief an activity to illustrate the property of inertia of rest. Question 3. Describe in brief an activity to illustrate the property of inertia of rest. Question 4. Give few examples of Newton’s third law of motion. Question 5. Two friends on roller-skates are standing 5 m apart facing each other. One of them throws a ball of 2 kg towards the other, who catches it. How will this activity affect the position of the two? Explain your answer. [NCERT Exemplar] Question 6. Why does an athlete puts some sands or cushion on the ground while high jumping? Question 6. Why does an athlete puts some sands or cushion on the ground while high jumping? Question 7...
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