A thin rod of length L and mass M is bent at its midpoint into two halves so that the angle between them is 90°. The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is : 2008 (1) ML2/6 (2) √2ML2/24 (3) ML2/24 (4) ML2/12

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class 10 ohm's law

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class 10 video  what ohm's law? Ohm’s Law states that the current flowing through a conductor is directly proportional to the potential difference applied across its ends, provided the temperature and other physical conditions remain unchanged. Mathematically it can be represented as, objective question based on electric current open this link for objective    https://nexttopperinstitute.blogspot.com/2020/07/class-10th-objective-questions-on.html   Class 10       HOW TO ORGANISM REPRODUCE Question. 1(i) What is fertilisation? Distinguish between external fertilisation and internal fertilisation. (ii) What is the site of fertilisation in human beings? Answer. (i) Fertilisation is defined as the fusion of a male gamete (sperm) with a female gamete (an ovum or egg) to form a zygote during sexual reproduction. (ii) The site of fertilisation in human beings is in the fallopian tube of female reproductive system. Question.2 Define th...
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error analysis objective questions dpp

NEXT TOPPER INSTITUTE  FOR YOU  1.     In an experiment the percentage of error occurred in the measurement of physical quantities A,B,C and D   are 1% ,2%, 3% and 4% respectively . then the maximum percentage of error in the measurement x where x =A 2 B 1/2 /c 1/3 D 3 will be                                             NEET 2019 a.      10%                b. 3/13%                c.   -10%                                d. 16% 2.   ...
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Kirchhoff law problem and equivalent resistance

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1. using Kirchhoff law find the current in following branch answer     AB:(5/8) A, CA: (5/2) A, DEB: (15/8) A AD: (15/8) A, CD: 0 A, BC: (5/2) A 2.  using Kirchhoff law find the current in following branch   Answer  current in branch AB= (4/17) A In branch BC = (6/17) A In branch CD = (4/17) A In branch AD= (6/17) A In branch BD = (-2/17) A Total Current =(4/17) +(6/17)+(-4/17)+(6/17)+(-2/17)=(10/17) A 4. find R Equivalent 
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class 12 chapter 3 current questions

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1.   Calculate i 1 , i 2 , i 3 2.   Calculate current in each branch  Using Kirchhoff’s rules                                           cbse 2017      3. calculate the current through the 40 Ω and 20 Ω resistors in the following circuit : Using Kirchhoff’s rules, cbse 2019  4.
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current chapter 3 class 12 objective dpp2

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class 10 chapter 10 cbse previous year all question

1.     NEXT TOPPER INSTITUTE हम आपके सपनो को साकार करेंगे   An object 3.0 cm high is placed perpendicular to the principal axis of a concave lens of focal length 30 . the image is formed at a distance of 10.cm from the lens calculate   distance at which object is placed ,size and nature of image formed . 2.     A concave lens has focal length of 20 cm .at what distance from the lens ,a 5  cm tall object be placed so that it formed an image at 15 cm from the lens . also calculate the size of the image formed ? 3.     Find the power of a concave lens of focal length 2 m. 4.     An object of height 5  cm is placed perpendicular to the principal axis of a concave lens of focal length 10 cm. if the distance of the object from the optical center  of the lens is 20 cm determine the position ,nature and size of the image formed using the lens formula . 5.     The image of an object formed by a...
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current objective question for cbse, jee , neet class12 chapter 3

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NEXT TOP PER INSTITUTE Dpp current questions 1.      1.  How many electrons per second flow through the cross sectional of a conductor so that the conductor carries a current of 1 ampere? a.      6.00 x 10 16 /sec       b.       6.00 x 10 17 /sec          c.        6.00 x 10 19 /sec     d.  6.25 x 10 18 /sec .       2.     2.   In a discharge tube the number of hydrogen ions drifting across a cross section per second is 1.0 X 10 18 , while the number of electrons drifting in opposite direction across that of cross section is 2.7 x 10 18  per second . calculate the total current crossing the given cross section . a.        0.6 A                        ...
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Motilal nehru public school jind class 9th dpp 1 Newton's law of motion all level question

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please download in pdf  click here  👇👇👇👇👇👇👇👇 https://knowingonline.in/2020/07/27/class-ix-newtons-law-of-motion/ Question 1. Deduce Newton’s first law from the second law. Question 2. When small boy is trying to push a heavy stone, mention various forces acting on the stone. Question 3. Describe in brief an activity to illustrate the property of inertia of rest. Question 3. Describe in brief an activity to illustrate the property of inertia of rest. Question 4. Give few examples of Newton’s third law of motion. Question 5. Two friends on roller-skates are standing 5 m apart facing each other. One of them throws a ball of 2 kg towards the other, who catches it. How will this activity affect the position of the two? Explain your answer. [NCERT Exemplar] Question 6. Why does an athlete puts some sands or cushion on the ground while high jumping? Question 6. Why does an athlete puts some sands or cushion on the ground while high jumping? Question 7...
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