2.Two charges each 1๐๐ are at p (2๐ ̂ +3๐ ̂ +๐ ̂) m and Q (๐ ̂ +๐ ̂ -๐ ̂) m . Then the force between them is …………………. 1.100N 2.10N 3.10^4 dyne 4.100 dyne
Education is a part of Life
Kirchhoff law problem and equivalent resistance
1. using Kirchhoff law find the current in following branch answer AB:(5/8) A, CA: (5/2) A, DEB: (15/8) A AD: (15/8) A, CD: 0 A, BC: (5/2) A 2. using Kirchhoff law find the current in following branch Answer current in branch AB= (4/17) A In branch BC = (6/17) A In branch CD = (4/17) A In branch AD= (6/17) A In branch BD = (-2/17) A Total Current =(4/17) +(6/17)+(-4/17)+(6/17)+(-2/17)=(10/17) A 4. find R Equivalent
Comments