From a circular disc of radius R and mass 9M , a small disc of radius R/3 is removed from the disc . The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through o is 4M๐‘…^2 40/9M๐‘…^2 10M๐‘…^2 37/9M๐‘…^2

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Kirchhoff law problem and equivalent resistance

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1. using Kirchhoff law find the current in following branch answer     AB:(5/8) A, CA: (5/2) A, DEB: (15/8) A AD: (15/8) A, CD: 0 A, BC: (5/2) A 2.  using Kirchhoff law find the current in following branch   Answer  current in branch AB= (4/17) A In branch BC = (6/17) A In branch CD = (4/17) A In branch AD= (6/17) A In branch BD = (-2/17) A Total Current =(4/17) +(6/17)+(-4/17)+(6/17)+(-2/17)=(10/17) A 4. find R Equivalent 
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current objective question for cbse, jee , neet class12 chapter 3

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NEXT TOP PER INSTITUTE Dpp current questions 1.      1.  How many electrons per second flow through the cross sectional of a conductor so that the conductor carries a current of 1 ampere? a.      6.00 x 10 16 /sec       b.       6.00 x 10 17 /sec          c.        6.00 x 10 19 /sec     d.  6.25 x 10 18 /sec .       2.     2.   In a discharge tube the number of hydrogen ions drifting across a cross section per second is 1.0 X 10 18 , while the number of electrons drifting in opposite direction across that of cross section is 2.7 x 10 18  per second . calculate the total current crossing the given cross section . a.        0.6 A                        ...
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Two rigid boxes containing different ideal gases are placed on a table . Box A contains one mole of nitrogen at temperature ๐‘‡_๐‘œ , while box B contains one mole of helium at temperature 7/3 ๐‘‡_๐‘œ . The boxes are then put into thermal contact with each other and heat flows between them until the gases reach a common final temperature (ignore the heat capacity of boxes and heat exchange will happen only between boxes ) . Then the final temperature of the gases in terms of ๐‘‡_๐‘œ is 7/3 ๐‘‡_๐‘œ 3/2 ๐‘‡_๐‘œ 5/2 ๐‘‡_๐‘œ 3/7 ๐‘‡_๐‘œ

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