In the circuit shown in the figure , the ac sources gives a voltage v=20 cos2000𝑡 . Neglecting sources resistance , the voltmeter and ammeter reading will be (√2=1.4 ) 0v ,0.47A 1.68v , 0.47A 0V ,1.4A 5.6V , 1.4A
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Kirchhoff law problem and equivalent resistance
1. using Kirchhoff law find the current in following branch answer AB:(5/8) A, CA: (5/2) A, DEB: (15/8) A AD: (15/8) A, CD: 0 A, BC: (5/2) A 2. using Kirchhoff law find the current in following branch Answer current in branch AB= (4/17) A In branch BC = (6/17) A In branch CD = (4/17) A In branch AD= (6/17) A In branch BD = (-2/17) A Total Current =(4/17) +(6/17)+(-4/17)+(6/17)+(-2/17)=(10/17) A 4. find R Equivalent
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